If the exterior angles of a pentagon are x°, (x + 5)°, (x + 10)°, (x + 15)° and (x + 20)°, find x
-
A.
118o -
B.
72o -
C.
62o -
D.
36o
Correct Answer: Option C
Explanation
The sum of the exterior angles of a regular polygon = 360°.
(therefore x + (x + 5) + (x + 10) + (x + 15) + (x + 20) = 360°)
(5x + 50 = 360° implies 5x = 360° – 50° = 310°)
(x = frac{310°}{5} = 62°)