If the surface area of a sphere increased by 44%, find the percentage increase in diameter

A.
44 
B.
30 
C.
22 
D.
20
Correct Answer: Option D
Explanation
Surface Area of Sphere A = 4(pi r^2)
∴ A = 4(pi)(frac{(D)^2}{2})
= (frac{(D)^2}{2})
= (pi)D^{2}
When increased by 44% A = (frac{144 pi D^2}{100})
(pi)(frac{(12D)^2}{10}) = (pi)(frac{(6D)^2}{5})
Increase in diameter = (frac{6D}{5}) – D = (frac{1}{5})D
Percentage increase = (frac{1}{5}) x (frac{1}{100})%
= 20%