If (x + 3) varies directly as y and x = 3 when y = 12, what is the value of x when y = 8?
-
A.
1 -
B.
(frac{1}{2}) -
C.
(-frac{}{}) -
D.
-1
Correct Answer: Option A
Explanation
((x+3) propto y\
∴x + 3 = kyhspace{1mm}whenhspace{1mm}x = 3, y = 12\
3+3 = 12k\
∴ k = frac{1}{2}\
Longrightarrow x + 3 = frac{1}{2}y) to find x when y = 8
(x + 3 = frac{1}{2}times 8\
x=4-3\
x = 1)