If x2 + kx + (frac{16}{9}) is a perfect square, find the value of k
-
A.
(frac{8}{3}) -
B.
(frac{7}{3}) -
C.
(frac{5}{3}) -
D.
(frac{2}{3})
Correct Answer: Option A
Explanation
x2 + kx + (frac{16}{9}); Perfect square
But, b2 – 4ac = 0, for a perfect square
where a – 1; b = k; c = (frac{16}{9})
k2 – 4(1) x (frac{16}{9}) = 0
k2 – (frac{64}{9}) = 0
k2 = (frac{64}{9})
k = (sqrt{frac{64}{9}})
k = (frac{8}{3})