Home » If y = 243(4x + 5)-2, find (frac{dy}{dx}) when x = 1

If y = 243(4x + 5)-2, find (frac{dy}{dx}) when x = 1

If y = 243(4x + 5)-2, find (frac{dy}{dx}) when x = 1
  • A.
    (frac{-8}{3})
  • B.
    (frac{3}{8})
  • C.
    (frac{9}{8})
  • D.
    -(frac{8}{9})
Correct Answer: Option A
Explanation

y = 243(4x + 5)-2, find (frac{dy}{dx})
= -1944(4x + 5)-3
= 1944(9)-3
(frac{dy}{dx}) when x = 1
= -(frac{1944}{9^3})
= -(frac{1944}{729})
= (frac{-8}{3})

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