If y = 3t

^{3}+ 2t^{2}– 7t + 3, find (frac{dy}{dt}) at t = -1-
**A.**

-1 -
**B.**

1 -
**C.**

-2 -
**D.**

2

##### Correct Answer: Option C

##### Explanation

y = 3t^{3} + 2t^{2} – 7t + 3

(frac{dy}{dt}) = 9t^{2} + 4t – 7

When t = -1

(frac{dy}{dt}) = 9(-1)^{2} + 4(-1) – 7

= 9 – 4 -7

= 9 – 11

= -2