In a figure, PQR = 60

^{o}, PRS = 90^{o}, RPS = 45^{o}, QR = 8cm. Determine PS-
**A.**

2(sqrt{3})cm -
**B.**

4(sqrt{6})cm -
**C.**

2(sqrt{6})cm -
**D.**

8(sqrt{6})cm -
**E.**

8cm

##### Correct Answer: Option B

##### Explanation

From the diagram, sin 60^{o} = (frac{PR}{8})

PR = 8 sin 60 = (frac{8sqrt{3}}{2})

= 4(sqrt{3})

Cos 45^{o} = (frac{PR}{PS}) = (frac{4 sqrt{3}}{PS})

PS Cos45^{o} = 4(sqrt{3})

PS = 4(sqrt{3}) x 2

= 4(sqrt{6})