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In a geometric progression, the first term is 153 and the sixth term is (frac{17}{27})….

In a geometric progression, the first term is 153 and the sixth term is (frac{17}{27}). The sum of the first four terms is
  • A.
    (frac{860}{3})
  • B.
    (frac{680}{3})
  • C.
    (frac{608}{3})
  • D.
    (frac{680}{3})
Correct Answer: Option B
Explanation

a = 153 – 1st term, 6th term = (frac{17}{27})
nth term = arn
Sn = a(1 – rn) where r

6th term = 153(frac{1 – 0.4^4}{1 – 0.4})
= (frac{680}{3})