In a recent zonal championship games involving 10 teams, teams X and Y were given probabilities (frac{2}{5}) and (frac{1}{3}) respectively of winning the gold in the football event. What is the probability that either team will win the gold?

A.
(frac{2}{15}) 
B.
(frac{7}{15}) 
C.
(frac{11}{15}) 
D.
(frac{13}{15})
Correct Answer: Option C
Explanation
p(x) = (frac{2}{5}) p(y) = (frac{1}{3})
p(x or y) = p(x ∪ y)
= p(x) + p(y)
= (frac{2}{5}) + (frac{1}{3})
= (frac{11}{5})