Home » In (bigtriangleup)PQR, PQ = 10cm, QR = 8cm and RP = 6cm, the perpendicular RS…

In (bigtriangleup)PQR, PQ = 10cm, QR = 8cm and RP = 6cm, the perpendicular RS…

In (bigtriangleup)PQR, PQ = 10cm, QR = 8cm and RP = 6cm, the perpendicular RS is drawn from R to PQ. Find the length of RS
  • A.
    4cm
  • B.
    32cm
  • C.
    (frac{30}{7})
  • D.
    (frac{40}{7})
  • E.
    4.8cm
Correct Answer: Option E
Explanation

Cos Q = (frac{r^2 + p^2 – q^2}{2rp})
= (frac{10^2 + 8^2 – 6^2}{2(10)(8)})
= (frac{164 – 36}{160})
= (frac{128}{160})
= 0.8
Q = Cos-1 o.8
= 37o x rep. from rt

(frac{x}{sin 37^o}) = (frac{8}{sin 90^o})
but sin 90o = 1
x = 8 sin 37o
x = 4.8cm