Home » In the diagram above; O is the centre of the circle and |BD| = |DC|….

In the diagram above; O is the centre of the circle and |BD| = |DC|….

In the diagram above; O is the centre of the circle and |BD| = |DC|. If ∠DCB = 35°, find ∠BAO.

A.
20^o
B.
25^o
C.
30^o
D.
35^o
E.
40^o

Correct Answer: Option A

Explanation

< DBC = 35° (base angles of an isosceles triangle)

< CDB = 180° – (35° + 35°)

= 110°

< ADB = 70°; < ADB = 90°

(therefore) < BAO = 180° – (70° + 90°)

= 20°