In the diagram above PQT is a tangent to the circle QRS at Q. Angle QTR = 48° and ∠QRT = 95°. Find ∠QRT
-
A.
48o -
B.
45o -
C.
37o -
D.
32o -
E.
30o
Correct Answer: Option C
Explanation
∠RQT = 180° – (95° + 48°) = 73°
∠OQR = 90° – 37° = 53°
∠QOR = 180° – (53° + 53°) = 74°
QSR = 74°/2 = 37°