In the diagram, DE||BC, |AD| = x cm and |DB| = |AE| = ycm. Find |CE| in terms of x and y
-
A.
x -
B.
(frac{x^2}{y}) -
C.
(frac{y}{x^2}) -
D.
(frac{y^2}{x})
Correct Answer: Option D
Explanation
(frac{x}{x+y}=frac{y}{x+CE}\
xy + xCE = xy + y^2\
∴xCE = y^2\
CE=frac{y^2}{x})