In the diagram O is the center of the circle, if ∠QRS = 62o, find the value of ∠SQR.
-
A.
14o -
B.
28o -
C.
31o -
D.
45o -
E.
90o
Correct Answer: Option B
Explanation
< QSR = 90° (angle in a semi-circle)
(therefore) < SQR = 180° – (90° + 62°)
= 28°
In the diagram O is the center of the circle, if ∠QRS = 62o, find the value of ∠SQR.
< QSR = 90° (angle in a semi-circle)
(therefore) < SQR = 180° – (90° + 62°)
= 28°