In the diagram, PR is a diameter, ∠PRQ = (3x-8)

^{o}and ∠RPQ = (2y-7)^{o}. s x in terms of y-
**A.**

(x=frac{75-2y}{3}) -
**B.**

(x=frac{105-3y}{2}) -
**C.**

(x=frac{105-2y}{3}) -
**D.**

(x=frac{75-3y}{2})

##### Correct Answer: Option C

##### Explanation

180 = ∠RPQ + ∠PRQ + ∠PQR Since PQR = 90 (theorem: angle in a semi circle)

180 = ∠RPQ + ∠PRQ + 90 => 180^{o} = (3x-8)^{o}+(2y-7)^{o}+90^{o}; 90+8+7 = 3x+2y =>(frac{105-2y}{3}=x)