Home » In the diagram, PR is a diameter, ∠PRQ = (3x-8)o and ∠RPQ = (2y-7)o. s…

In the diagram, PR is a diameter, ∠PRQ = (3x-8)o and ∠RPQ = (2y-7)o. s…

In the diagram, PR is a diameter, ∠PRQ = (3x-8)o and ∠RPQ = (2y-7)o. s x in terms of y
  • A.
    (x=frac{75-2y}{3})
  • B.
    (x=frac{105-3y}{2})
  • C.
    (x=frac{105-2y}{3})
  • D.
    (x=frac{75-3y}{2})
Correct Answer: Option C
Explanation

180 = ∠RPQ + ∠PRQ + ∠PQR Since PQR = 90 (theorem: angle in a semi circle)
180 = ∠RPQ + ∠PRQ + 90 => 180o = (3x-8)o+(2y-7)o+90o; 90+8+7 = 3x+2y =>(frac{105-2y}{3}=x)

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