Home » In the diagram, PR is a diameter, ∠PRQ = (3x-8)o and ∠RPQ = (2y-7)o. s…

In the diagram, PR is a diameter, ∠PRQ = (3x-8)o and ∠RPQ = (2y-7)o. s…

In the diagram, PR is a diameter, ∠PRQ = (3x-8)^o and ∠RPQ = (2y-7)^o. s x in terms of y

A.
(x=frac{75-2y}{3})
B.
(x=frac{105-3y}{2})
C.
(x=frac{105-2y}{3})
D.
(x=frac{75-3y}{2})

Correct Answer: Option C

Explanation

180 = ∠RPQ + ∠PRQ + ∠PQR Since PQR = 90 (theorem: angle in a semi circle)
180 = ∠RPQ + ∠PRQ + 90 => 180^o = (3x-8)^o+(2y-7)^o+90^o; 90+8+7 = 3x+2y =>(frac{105-2y}{3}=x)