In the diagram, QPS = SPR, PR = 9cm. PQ = 4cm and QS = 3cm, find SR.
-
A.
6(frac{3}{4})cm -
B.
3(frac{3}{8})cm -
C.
4(frac{3}{8})cm -
D.
2(frac{3}{8})cm
Correct Answer: Option A
Explanation
Using angle bisector theorem: line PS bisects angle QPR
QS/QP = SR/PR
3/4 = SR/9
4SR = 27
SR = (frac{27}{4})
= 6(frac{3}{4})cm