Home » In the diagram, SQ = 4cm, PT = 7cm. /TR/ = 5cm and ST//OR. If /SP/ = xcm, find the value of x

In the diagram, SQ = 4cm, PT = 7cm. /TR/ = 5cm and ST//OR. If /SP/ = xcm, find the value of x

In the diagram, SQ = 4cm, PT = 7cm. /TR/ = 5cm and ST//OR. If /SP/ = xcm, find the value of x
  • A.
    5.6
  • B.
    6.5
  • C.
    6.6
  • D.
    6.8
Correct Answer: Option A
Explanation

(frac{/PS/}{/PQ/} = frac{/PT/}{/PR/})
(frac{x}{4 + x} = frac{7}{7 + 5})
(frac{x}{4 + x} = frac{7}{12})
(2x = 7)(4 + x); 12x = 28 + 7x
12x – 7x = 28
5x = 28
x = (frac{28}{5})
x = 5.6