In the diagram, TS is a tangent to the circle at S. |PR| and o. Calculate
- A.
54o - B.
44o - C.
34o - D.
27o
Correct Answer: Option A
Explanation
In the diagram above, x1 = 180o – 117o = 63o(opposite angles of a cyclic quad.)
x1 = x2 (base angles of isos. (Delta))
x1 + x2 + (alpha) = 180o (sum of angles of a (Delta)
63o + 63o + (alpha) = 180o
(alpha) = 180o – (63 + 63)o
= 54o