In the figure above, PQRS is a circle with ST//RQ. Find the value of x PT = PS.

**A.**

70^{o}**B.**

55^{o}**C.**

40^{o}**D.**

35^{o}

##### Correct Answer: Option B

##### Explanation

PQRS is a cyclic quad^{^}P = 180 – 110 (opp ∠s of a cyclic quad)^{^}P = 70

In ΔPTS, ^{^}S = ^{^}T (base ∠s of Isc Δ)

∴^{^}T = (180-70) / 2

= 110/2

= 55^{o}

But ^{^}T x(corr ∠)

∴x =55