In the figure, STQ = SRP, PT = TQ = 6cm and QS = 5cm. Find SR
-
A.
(frac{47}{5}) -
B.
5 -
C.
(frac{32}{5}) -
D.
(frac{22}{5})
Correct Answer: Option A
Explanation
From similar triangle, (frac{QS}{QP} = frac{TQ}{QR} = frac{5}{12} = frac{6}{QR})
QT = (frac{6 times 12}{5} = frac{72}{5} = SR = QR – QS)
= (frac{72}{5} – 5 = frac{72 – 25}{5})
= (frac{47}{5})