In the parallelogram PQRS, PE is perpendicular to QR. Find the area of the parallelogram.

A.
60cm^{2} 
B.
65cm^{2} 
C.
72cm^{2} 
D.
144cm^{2} 
E.
156cm^{2}
Correct Answer: Option D
Explanation
By Pythagoras, PE^{2} = 13^{2} – 5^{2}
= 169 – 144 = 144
h = PE = 144 = 12cm,
Area of 11gm = b x h
QR = b =(5 + 7)cm = 12cm
area = 12 x 12
= 144cm^{2}