In this fiqure, PQ = PR = PS and SRT = 68(^o). Find QPS 

In this fiqure, PQ = PR = PS and SRT = 68(^o). Find QPS 

Correct Answer: Option A

Explanation

Since PQRS is quadrilateral

2y + 2x + QPS = 360(^o)

i.e. (y + x) + QPS = 360(^o) 

QPS = 360(^o) – 2 (y + x)

But x + y + 68(^o) = 180(^o)

There; x + y = 180(^o) – 68(^o) = 112(^o)

QPS = 360 – 2(112(^o))

= 360(^o) – 224 = 136(^o)

There is an explanation video available below.