Make p the subject of the relation: q = (frac{3p}{r} + frac{s}{2})
-
A.
p = (frac{2q – rs}{6}) -
B.
p = 2qr – sr – 3 -
C.
p = (frac{2qr – s}{6}) -
D.
p = (frac{2qr – rs}{6})
Correct Answer: Option D
Explanation
q = (frac{3p}{r} + frac{s}{2})
q = (frac{6p + rs}{2r})
6p + rs = 2qr
6p = 2qr – rs
p = (frac{2qr – rs}{6})