Make R the subject of the fomula S = (sqrt{frac{2R + T}{2RT}})

A.
R = (frac{T}{(TS^2 + 1)}) 
B.
R = (frac{T}{2(TS^2 – 2)}) 
C.
R = (frac{T}{2(TS^2 + 1)}) 
D.
R = (frac{R}{2(TS^2 + 1)})
Correct Answer: Option B
Explanation
S = (sqrt{frac{2R + T}{2RT}})
Squaring both sides,
(S^{2} = frac{2R + T}{2RT})
(S^{2} (2RT) = 2R + T)
(2S^{2} RT – 2R = T)
(R = frac{T}{2TS^{2} – 2})
= (frac{T}{2(TS^{2} – 1)}