Make T the subject of the equation (frac{av}{1 – v}) = (sqrt{frac{2v + T}{a + 2T}})
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A.
T = (frac{3av}{1 – v}) -
B.
T = (frac{1 + v}{2a^2v^3}) -
C.
T = (frac{2v(1 – v)^3 – a^4v^3}{2a^3v^3 + (1 – v)^2}) -
D.
(frac{2v(1 – v)^3 – a^4 v^3}{2a^3v^ 3 – (1 – v)^3})
Correct Answer: Option D
Explanation
(frac{av}{1 – v}) = (sqrt{frac{2v + T}{a + 2T}})
(frac{(av)^3}{(1 – v)^3}) = (frac{2v + T}{a + 2T})
(frac{a^3v^3}{(1^3 – v)^3}) = (frac{2v + T}{a + 2T})
= (frac{2v(1 – v)^3 – a^4 v^3}{2a^3v^ 3 – (1 – v)^3})