Make x the subject of the equation a(b + c) + (frac{5}{d}) – 2 = 0

A.
c = (frac{2d – 5 – b}{ad}) 
B.
c = (frac{2d – 5 – abd}{ad}) 
C.
c = (frac{2d – 5 – ab}{ad}) 
D.
c = (frac{5 – 2d – b}{ad})
Correct Answer: Option B
Explanation
a(b + c) + (frac{5}{d}) – 2 = 0
ab + ac + (frac{5}{d}) – 2 = 0
abd + (frac{acd}{d}) + 5 – 2 = ab + ac + 5 – 2d
acd = 2d – 5 – abd
c = (frac{2d – 5 – abd}{ad})