Make y the subject of the formula Z = x(^2) + (frac{1}{y^3})
-
A.
y = (frac{1}{(Z – x^2)^3}) -
B.
y = (frac{1}{(Z + x^2)^{frac{1}{3}}}) -
C.
y = (frac{1}{(Z – x^2)^{frac{1}{3}}}) -
D.
y = (frac{1}{sqrt[3]{Z} – sqrt[3]{x^2}})
Correct Answer: Option C
Explanation
Z = x(^2) + (frac{1}{y^3})
Z – x(^2) = (frac{1}{y^3})
y(^3) = (frac{1}{Z – x^2})
y = (sqrt[3]{frac{1}{Z – x^2}})
∴ y = (frac{1}{sqrt[3]{Z – x^2}})
y = (frac{1}{(Z – x^2)^{frac{1}{3}}})