Marks 1 2 3 4 5 Frequency 2y – 2 y – 1 3y -…

Marks	1	2	3	4	5
Frequency	2y – 2	y – 1	3y – 4	3 – y	6 – 2y

The table above is the distribution of data with mean equals to 3. Find the value of y.

Correct Answer: Option B

Explanation

Marks (x)	1	2	3	4	5
Frequency (f)	2y – 2	y – 1	3y – 4	3 – y	6 – 2y	3y + 2
fx	2y – 2	2y – 2	9y – 12	12 – 4y	30 – 10y	26 – y

Mean = (frac{sum fx}{sum f})

(3 = frac{26 – y}{3y + 2})

(3(3y + 2) = 26 – y)

(9y + 6 = 26 – y)

(9y + y = 26 – 6)

(10y = 20 implies y = 2)

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