Obtain a maximum value of the function f(x) x

^{3}– 12x + 11-
**A.**

-5 -
**B.**

-2 -
**C.**

2 -
**D.**

27

##### Correct Answer: Option D

##### Explanation

f(x) = x^{3} – 12x + 11

(frac{df(x)}{dx)}) = 3x^{2} – 12 = 0

∴ 3x^{2} – 12 = 0 (to) x^{2}m = 4

x = (pm)2, f(+2) = 8 – 24 + 11 = -15

= f(-2) = (-8) + 24 + 11

= 35 – 8 = 27

∴ maximum value = 27