p = begin vmatrix x & 3 & 0 \ 2 & y & 3\ 4

p = (begin{vmatrix} x & 3 & 0 \ 2 & y & 3\ 4 & 2 & 4 end{vmatrix})

Q = (begin{vmatrix} x & 2 & z \ 3 & y & 2\ 0 & 3 & z end{vmatrix}) Where p^T is the transpose P calculate /p^T/ when x = 0, y = 1 and z = 2

• A. 48
• B. 24
• C. -24
• D. -48

Correct Answer: Option B

Explanation

p = (begin{vmatrix} 0 & 3 & 0 \ 2 & 1 & 3\ 4 & 2 & 2 end {vmatrix})
P^T = (begin{vmatrix} 0 & 2 & 4 \ 2 & 1 & 3\ 0 & 3 & 2 end {vmatrix})
/p^T/ = (begin{vmatrix} 0 & 2 & 4 \ 3 & 1 & 3\ 0 & 3 & 2 end {vmatrix})
= 0 [2 – 6] – 2[6 – 0] + 4[9 – 0]
= 0 – 12 + 36 = 24