PRSQ is a trapezium of area 14cm

^{2}in which PQ||RS. If PQ = 4cm and SR = 3cm, Find the area of SQR in cm^{2}-
**A.**

7.0 -
**B.**

6.0 -
**C.**

5.2 -
**D.**

5.0

##### Correct Answer: Option B

##### Explanation

Area of trapezium = 14cm^{2}

Area of trapezium = (frac{1}{2})(a + b)h

14 = (frac{1}{2})(4 + 3)h

14 = (frac{7}{2})h

h = (frac{14 times 2}{7})

= 4

Area of SQR = (frac{1}{2})(3 x 4)

= (frac{12}{2})

= 6.0