Solve for x, If (frac{frac{2}{x}}{frac{p^2 + p^2}{p^2 + p^2}}) = m
-
A.
(frac{4pq}{m(p + q)}) -
B.
(frac{2p^2q^2}{m(q^2 + p^2)}) -
C.
(frac{2pq}{m(q^2 + p^2)}) -
D.
(frac{2p^2q^2}{m(p^2)})
Correct Answer: Option B
Explanation
(frac{1}{p^2}) + (frac{1}{q^2}) = (frac{q^2 + p^2}{p^2 + q^2})
(frac{frac{2}{x}}{frac{p^2 + p^2}{p^2 + p^2}})
m = (frac{2p^2q^2}{x(p^2 + q^2)})
= m2p2q2 = m x (p2 + q2)
x = (frac{2p^2q^2}{m(q^2 + p^2)})