Solve the equation (3y^2 = 27y)
-
A.
y = o or 3 -
B.
y = 0 or 9 -
C.
y = -3 or 3 -
D.
y = 3 or 9
Correct Answer: Option B
Explanation
(3y^2 = 27y\
3y^2 – 27y = 0\
3y(y – 9) = 0\
3y = 0 or y – 9 = 0\
y = 0 or y = 9\
y = 0 or 9)
(3y^2 = 27y\
3y^2 – 27y = 0\
3y(y – 9) = 0\
3y = 0 or y – 9 = 0\
y = 0 or y = 9\
y = 0 or 9)