Solve the equations
m2 + n2 = 29
m + n = 7
m2 + n2 = 29
m + n = 7
-
A.
(2, 3) and ( 3, 5) -
B.
(2, 5) and (5, 2) -
C.
(5, 2) and ( 5, 3) -
D.
(5, 3) and (3, 5)
Correct Answer: Option B
Explanation
m2 + n2 = 29 …….(1)
m + n = 7 …………(2)
From (2),
m = 7 – n
but m2 + n2 = 29, substituting;
(7-n)2 + n2 = 29
49 – 14n + n2 + n2 = 29
=> 2n2 -14n + 20 = 0
Thus n2 -7n + 10 = 0
Factorizing;
(n-5)(n-2) = 0
n – 5 = 0, => n = 5
n – 2 = 0, => n = 2.
When n = 5,
m + n = 7, => m = 2,
When n = 2,
m + n = 7, => m = 5.
Thus (m,n) = (5,2) and (2,5)