Solve the system of equation 2x + y = 32, 33y – x = 27

Solve the system of equation 2^{x + y} = 32, 3^{3y – x} = 27

Correct Answer: Option A

Explanation

2^{x + y} = 32, 3^{3y – x} = 27
2^{x + y} = 2⁵
3^{3y + x} = 3³
x + y = 5
(frac{3y – x = 3}{4y = 8})
y = 2