Solve the system of equation 2

^{x + y}= 32, 3^{3y – x}= 27-
**A.**

(3, 2) -
**B.**

(-3, 2) -
**C.**

(3, -2) -
**D.**

(-3, -2) -
**E.**

(2, 2)

##### Correct Answer: Option A

##### Explanation

2^{x + y} = 32, 3^{3y – x} = 27

2^{x + y} = 2^{5}

3^{3y + x} = 3^{3}

x + y = 5

(frac{3y – x = 3}{4y = 8})

y = 2