Subtract (frac{1}{2})(a – b – c) from the sum of (frac{1}{2})(a – b + c) and (frac{1}{2})
(a + b – c)
(a + b – c)
-
A.
(frac{1}{2}) (a + b + c) -
B.
(frac{1}{2}) (a – b – c) -
C.
(frac{1}{2}) (a – b + c) -
D.
(frac{1}{2}) (a + b – c)
Correct Answer: Option A
Explanation
(frac{1}{2})(a – b + c) + (frac{1}{2})(a + b – c) – [(frac{1}{2}) (a – b – c)]
(frac{1}{2}a – frac{1}{2}b + frac{1}{2}c + frac{1}{2}a + frac{1}{2}b – frac{1}{2}c – frac{1}{2}a + frac{1}{2}b + frac{1}{2}c)
= (frac{1}{2}a + frac{1}{2}b + frac{1}{2}c)
= (frac{1}{2}(a + b + c))