The 3rd term of an arithmetic progression is 9 and the 7th term is 29. Find the 10th term of the progression

A.
44 
B.
165 
C.
165 
D.
44
Correct Answer: Option A
Explanation
3rd term : a + 2d = 9 …….(1)
7th term : a + 6d = 29 ……(2)
(2) – (1): 4d = 20
:. d = ^{20/}_{4} = 5
From (1) : a + 2(5) = 9
a – 10 = 9
:. a = 9 + 10 = 1
:. 10th term of A.P is a + 9d = 1 + 9 (5)
= 1 – 45 = 44