The ages of three men are in the ratio 3:4:5. If the difference between the ages of the oldest and youngest is 18 years, find the sum of the ages of the three men
-
A.
45 years -
B.
72 years -
C.
108 years -
D.
216 years
Correct Answer: Option C
Explanation
Given that the ages are in the ratio 3: 4: 5.
Let the sum of their ages be t.
(therefore) The youngest age = (frac{3}{12} t)
The eldest age = (frac{5}{12} t)
(implies frac{5}{12} t – frac{3}{12} t = 18)
(frac{2t}{12} = 18 implies t = frac{18 times 12}{2})
t = 108 years.
The sum of their ages = 108 years.