Home » The ages of three men are in the ratio 3:4:5. If the difference between the…

The ages of three men are in the ratio 3:4:5. If the difference between the…

The ages of three men are in the ratio 3:4:5. If the difference between the ages of the oldest and youngest is 18 years, find the sum of the ages of the three men

  • A.
    45 years
  • B.
    72 years
  • C.
    108 years
  • D.
    216 years
Correct Answer: Option C
Explanation

Given that the ages are in the ratio 3: 4: 5.

Let the sum of their ages be t.

(therefore) The youngest age = (frac{3}{12} t)

The eldest age = (frac{5}{12} t)

(implies frac{5}{12} t – frac{3}{12} t = 18)

(frac{2t}{12} = 18 implies t = frac{18 times 12}{2})

t = 108 years.

The sum of their ages = 108 years.

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