The angle of depression of a boat from the top of a cliff 10m high is 30. How far is the boat from the foot of the cliff?
-
A.
(frac{5√3m}{3}) -
B.
5√3m -
C.
10√3m -
D.
(frac{10√3m}{3})
Correct Answer: Option C
Explanation
RQP = 90o
PQS = 30o but
RQS = 90o = (frac{RS}{10})
RS = 10 tan 60o
RS = 10 tan 60o
RS = 10√3m