The angle of depression of a boat from the top of a cliff 10m high is 30. How far is the boat from the foot of the cliff?

A.
(frac{5√3m}{3}) 
B.
5√3m 
C.
10√3m 
D.
(frac{10√3m}{3})
Correct Answer: Option C
Explanation
RQP = 90^{o}
PQS = 30^{o} but
RQS = 90^{o} = (frac{RS}{10})
RS = 10 tan 60^{o}
RS = 10 tan 60^{o}
RS = 10√3m