The angle of elevation of the top of a vertical tower from a point A on the ground is 60

^{o}. From a point B, 2 units of distance further away from the foot of the tower, the angle of elevation of the tower is 45^{o}. Find the distance of A from the foot of the tower-
**A.**

3 + (sqrt{3}) -
**B.**

5 + (sqrt{3}) -
**C.**

3 – (sqrt{3}) -
**D.**

1 -
**E.**

(sqrt{3}) – 1