The diagram, MOPQ is a trapezium with QP||MO, MQ||NP, NQ||OP, |QP| = 9cm and the…

The diagram, MOPQ is a trapezium with QP||MO, MQ||NP, NQ||OP, |QP| = 9cm and the height of (Delta) QNP = 6cm, calculate the area of the trapezium.

Correct Answer: Option C

Explanation

Area of (Delta) QNP = (frac{1}{2} times 9 times 6 ) = 27cm²
Area of (Delta) QMN = Area of (Delta) QNP
= Area of (Delta) PNO (triangles between the same parallels)
Hence, area of the trapezium
3 x area of (Delta) QNP
= 3 x 27
= 81cm²