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The diagram shows the position of three ships A, B and C at sea. B…

The diagram shows the position of three ships A, B and C at sea. B is due north of C such that |AB| = |BC| and the bearing of B from A = 040°. What is the bearing of A from C

  • A.
    040o
  • B.
    070o
  • C.
    110o
  • D.
    290o
Correct Answer: Option D
Explanation

< ABC = 40° (alternate angles)

(therefore) < ACB = (frac{180° – 40°}{2})

= 70°

(therefore) Bearing of A from C = 360° – 70° 

= 290°

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