The first term a of an A.P is equal to twice the
common difference d. Find, in terms of d, the 5th
term of the A.P.
common difference d. Find, in terms of d, the 5th
term of the A.P.
-
A.
4d -
B.
5d -
C.
6d -
D.
a + 5d -
E.
2a + 4d
Correct Answer: Option C
Explanation
Tn = a + (n – 1)d; AP; a = 2d; Tn = 2d + (n – 1)d
T5 = 2d + (5 – 1)d = 2d + 4d = 6d