The H.C.F. of a2bx + ab2x and a2b – b2 is
-
A.
b -
B.
a + b -
C.
b(a (div) b) -
D.
abx(a2 – b2)
Correct Answer: Option B
Explanation
a2bx + ab2x; a2b – b2
abx(a + b); b(a2 – b2)
b(a + b)(a + b)
∴ H.C.F. = (a + b)
a2bx + ab2x; a2b – b2
abx(a + b); b(a2 – b2)
b(a + b)(a + b)
∴ H.C.F. = (a + b)