The midpoint of the segment of the line y = 4x + 3 which lies between the x-ax 1 is and the y-ax 1 is
-
A.
((frac{3}{2}), (frac{3}{2})) -
B.
((frac{2}{3}), (frac{3}{2})) -
C.
((frac{3}{8}), (frac{3}{2})) -
D.
(-(frac{3}{8}), (frac{3}{2}))
Correct Answer: Option D
Explanation
y = 4x + 3
when x = 0, y = 3 (to) (0, 3)
when y = 0, x = -(frac{3}{4}) (to) ((frac{3}{4}), 0)
mid-point (frac{0 + (-{frac{3}{4}})}{2}), (frac{3 + 0}{4})
-(frac{3}{8}), (frac{3}{2})