The minimum value of y in the equation y = x(^2) – 6x + 8 is
-
A.
8 -
B.
3 -
C.
7 -
D.
-1
Correct Answer: Option D
Explanation
y = x(^2) – 6x + 8
(frac{dy}{dx}) = 2x – 6
(frac{dy}{dx}) = 0
2x – 6 = 0
x = 3
(therefore) y = 3(^2) – 6(3) + 8
= 9 – 18 + 8
= -1