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The minimum value of y in the equation y = x(^2) – 6x + 8…

The minimum value of y in the equation y = x(^2) – 6x + 8 is

  • A.
    8
  • B.
    3
  • C.
    7
  • D.
    -1
Correct Answer: Option D
Explanation

y = x(^2) – 6x + 8
(frac{dy}{dx}) = 2x – 6
(frac{dy}{dx}) = 0
2x – 6 = 0
x = 3

(therefore) y = 3(^2) – 6(3) + 8

= 9 – 18 + 8

= -1