(begin{array}{c|c} oplus mod 10 & 2 & 4 & 6 & 8 \ hline 2 & 4 & 8 & 2 & 6 \4 & 8 & 6 & 4 & 2\ 4 & 8 & 6 & 4 & 2\ 6 & 2 & 4 & 6 & 8\ 8 & 6 & 2 & 8 & 4end{array})
The multiplication table above has modulo 10 on the set S = (2, 4, 6, 8). Find the inverse of 2
- A.
2 - B.
4 - C.
6 - D.
8
Correct Answer: Option A
Explanation
The inverse of 2 is 6 since 2 x 6 = 12; under mod 10
12 = 2 which is also the value required