The nth term of a sequence is given 3

^{1 – n}, find the sum of the first terms of the sequence.-
**A.**

(frac{13}{9}) -
**B.**

1 -
**C.**

(frac{1}{3}) -
**D.**

(frac{1}{9})

##### Correct Answer: Option A

##### Explanation

Tn = 3^{1 – n}

S_{3} = 3^{1 – 1} + 3^{1 – 2} + 3^{1 – 3}

= 1 + (frac{1}{3}) + (frac{1}{9})

= (frac{13}{9})