The nth term of a sequence is n2 – 6n – 4. Find the sum of the 3rd and 4th terms.
-
A.
24 -
B.
23 -
C.
-24 -
D.
-25
Correct Answer: Option D
Explanation
n2 – 6n – 4
For the 3rd term,
32 – 6(3) – 4
9 – 18 -4 = -13
For the 4th term,
42 – 6(4) – 4
16 – 24 – 4 = -12
Sum of both terms
-13 – 12 = -25
There is an explanation video available below.