The nth term of a sequence is n

^{2}– 6n – 4. Find the sum of the 3rd and 4th terms.-
**A.**

24 -
**B.**

23 -
**C.**

-24 -
**D.**

-25

##### Correct Answer: Option D

##### Explanation

n^{2} – 6n – 4

For the 3rd term,

3^{2} – 6(3) – 4

9 – 18 -4 = -13

For the 4th term,

4^{2} – 6(4) – 4

16 – 24 – 4 = -12

Sum of both terms

-13 – 12 = -25

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